gen_compile_commands: remove the warning about too few .cmd files

This warning was useful when users previously needed to manually
build the kernel and run this script.

Now you can simply do 'make compile_commands.json', which updates
all the necessary build artifacts and automatically creates the
compilation database. There is no more worry for a mistake like
"Oh, I forgot to build the kernel".

Now, this warning is rather annoying.

You can create compile_commands.json for an external module:

  $ make M=/path/to/your/external/module compile_commands.json

Then, this warning is displayed since there are usually less than
300 files in a single module.

Signed-off-by: Masahiro Yamada <masahiroy@kernel.org>
Reviewed-by: Nick Desaulniers <ndesaulniers@google.com>

1 files changed, 0 insertions, 10 deletions

diff --git a/scripts/gen_compile_commands.py b/scripts/gen_compile_commands.py
index 92ea0a2ee59e..19963708bcf8 100755
--- a/scripts/gen_compile_commands.py
+++ b/scripts/gen_compile_commands.py
@@ -21,11 +21,6 @@ _FILENAME_PATTERN = r'^\..*\.cmd$'
 _LINE_PATTERN = r'^cmd_[^ ]*\.o := (.* )([^ ]*\.c)$'
 _VALID_LOG_LEVELS = ['DEBUG', 'INFO', 'WARNING', 'ERROR', 'CRITICAL']
 
-# A kernel build generally has over 2000 entries in its compile_commands.json
-# database. If this code finds 300 or fewer, then warn the user that they might
-# not have all the .cmd files, and they might need to compile the kernel.
-_LOW_COUNT_THRESHOLD = 300
-
 
 def parse_arguments():
     """Sets up and parses command-line arguments.
@@ -236,11 +231,6 @@ def main():
     with open(output, 'wt') as f:
         json.dump(compile_commands, f, indent=2, sort_keys=True)
 
-    count = len(compile_commands)
-    if count < _LOW_COUNT_THRESHOLD:
-        logging.warning(
-            'Found %s entries. Have you compiled the kernel?', count)
-
 
 if __name__ == '__main__':
     main()