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| author | Alexey Khoroshilov <khoroshilov@ispras.ru> | 2010-11-12 01:05:14 +0300 |
|---|---|---|
| committer | Linus Torvalds <torvalds@linux-foundation.org> | 2010-11-12 18:55:31 +0300 |
| commit | 834b40380e93e36f1c9b48ec1d280cebe3d7bd8c (patch) | |
| tree | acb6c23488baaf50e1cabd218738281973616734 /kernel/range.c | |
| parent | aec04288904a7308f2900926902040e7a69ae2be (diff) | |
| download | linux-834b40380e93e36f1c9b48ec1d280cebe3d7bd8c.tar.xz | |
kernel/range.c: fix clean_sort_range() for the case of full array
clean_sort_range() should return a number of nonempty elements of range
array, but if the array is full clean_sort_range() returns 0.
The problem is that the number of nonempty elements is evaluated by
finding the first empty element of the array. If there is no such element
it returns an initial value of local variable nr_range that is zero.
The fix is trivial: it changes initial value of nr_range to size of the
array.
The bug can lead to loss of information regarding all ranges, since
typically returned value of clean_sort_range() is considered as an actual
number of ranges in the array after a series of add/subtract operations.
Found by Analytical Verification project of Linux Verification Center
(linuxtesting.org), thanks to Alexander Kolosov.
Signed-off-by: Alexey Khoroshilov <khoroshilov@ispras.ru>
Cc: Yinghai Lu <yinghai@kernel.org>
Cc: "H. Peter Anvin" <hpa@zytor.com>
Cc: Geert Uytterhoeven <geert@linux-m68k.org>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
Diffstat (limited to 'kernel/range.c')
| -rw-r--r-- | kernel/range.c | 2 |
1 files changed, 1 insertions, 1 deletions
diff --git a/kernel/range.c b/kernel/range.c index 471b66acabb5..37fa9b99ad58 100644 --- a/kernel/range.c +++ b/kernel/range.c @@ -119,7 +119,7 @@ static int cmp_range(const void *x1, const void *x2) int clean_sort_range(struct range *range, int az) { - int i, j, k = az - 1, nr_range = 0; + int i, j, k = az - 1, nr_range = az; for (i = 0; i < k; i++) { if (range[i].end) |