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author | Matthew Wilcox (Oracle) <willy@infradead.org> | 2022-05-18 06:36:55 +0300 |
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committer | Matthew Wilcox (Oracle) <willy@infradead.org> | 2022-08-02 19:34:03 +0300 |
commit | 8b5d143c95533aa18ac3b39b82568391a7225a61 (patch) | |
tree | 2dd911a2e81da889e3ed26f94f1f31037029cd09 /block | |
parent | cf948cbc35e80bbdde41fec0bb7f2a7c5e276ffb (diff) | |
download | linux-8b5d143c95533aa18ac3b39b82568391a7225a61.tar.xz |
block: Simplify read_part_sector()
That rather complicated expression is just trying to find the offset
of this sector within a page, and there are easier ways to express that.
Signed-off-by: Matthew Wilcox (Oracle) <willy@infradead.org>
Diffstat (limited to 'block')
-rw-r--r-- | block/partitions/core.c | 3 |
1 files changed, 1 insertions, 2 deletions
diff --git a/block/partitions/core.c b/block/partitions/core.c index a9a51bac42df..52871fa224ee 100644 --- a/block/partitions/core.c +++ b/block/partitions/core.c @@ -718,8 +718,7 @@ void *read_part_sector(struct parsed_partitions *state, sector_t n, Sector *p) goto out; p->v = page; - return (unsigned char *)page_address(page) + - ((n & ((1 << (PAGE_SHIFT - 9)) - 1)) << SECTOR_SHIFT); + return page_address(page) + offset_in_page(n * SECTOR_SIZE); out: p->v = NULL; return NULL; |