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-rw-r--r--kernel/locking/lockdep.c133
1 files changed, 123 insertions, 10 deletions
diff --git a/kernel/locking/lockdep.c b/kernel/locking/lockdep.c
index 7641bd407239..e97d08001437 100644
--- a/kernel/locking/lockdep.c
+++ b/kernel/locking/lockdep.c
@@ -760,7 +760,7 @@ static void lockdep_print_held_locks(struct task_struct *p)
* It's not reliable to print a task's held locks if it's not sleeping
* and it's not the current task.
*/
- if (p->state == TASK_RUNNING && p != current)
+ if (p != current && task_is_running(p))
return;
for (i = 0; i < depth; i++) {
printk(" #%d: ", i);
@@ -843,7 +843,7 @@ static int count_matching_names(struct lock_class *new_class)
}
/* used from NMI context -- must be lockless */
-static __always_inline struct lock_class *
+static noinstr struct lock_class *
look_up_lock_class(const struct lockdep_map *lock, unsigned int subclass)
{
struct lockdep_subclass_key *key;
@@ -851,12 +851,14 @@ look_up_lock_class(const struct lockdep_map *lock, unsigned int subclass)
struct lock_class *class;
if (unlikely(subclass >= MAX_LOCKDEP_SUBCLASSES)) {
+ instrumentation_begin();
debug_locks_off();
printk(KERN_ERR
"BUG: looking up invalid subclass: %u\n", subclass);
printk(KERN_ERR
"turning off the locking correctness validator.\n");
dump_stack();
+ instrumentation_end();
return NULL;
}
@@ -2304,7 +2306,56 @@ static void print_lock_class_header(struct lock_class *class, int depth)
}
/*
- * printk the shortest lock dependencies from @start to @end in reverse order:
+ * Dependency path printing:
+ *
+ * After BFS we get a lock dependency path (linked via ->parent of lock_list),
+ * printing out each lock in the dependency path will help on understanding how
+ * the deadlock could happen. Here are some details about dependency path
+ * printing:
+ *
+ * 1) A lock_list can be either forwards or backwards for a lock dependency,
+ * for a lock dependency A -> B, there are two lock_lists:
+ *
+ * a) lock_list in the ->locks_after list of A, whose ->class is B and
+ * ->links_to is A. In this case, we can say the lock_list is
+ * "A -> B" (forwards case).
+ *
+ * b) lock_list in the ->locks_before list of B, whose ->class is A
+ * and ->links_to is B. In this case, we can say the lock_list is
+ * "B <- A" (bacwards case).
+ *
+ * The ->trace of both a) and b) point to the call trace where B was
+ * acquired with A held.
+ *
+ * 2) A "helper" lock_list is introduced during BFS, this lock_list doesn't
+ * represent a certain lock dependency, it only provides an initial entry
+ * for BFS. For example, BFS may introduce a "helper" lock_list whose
+ * ->class is A, as a result BFS will search all dependencies starting with
+ * A, e.g. A -> B or A -> C.
+ *
+ * The notation of a forwards helper lock_list is like "-> A", which means
+ * we should search the forwards dependencies starting with "A", e.g A -> B
+ * or A -> C.
+ *
+ * The notation of a bacwards helper lock_list is like "<- B", which means
+ * we should search the backwards dependencies ending with "B", e.g.
+ * B <- A or B <- C.
+ */
+
+/*
+ * printk the shortest lock dependencies from @root to @leaf in reverse order.
+ *
+ * We have a lock dependency path as follow:
+ *
+ * @root @leaf
+ * | |
+ * V V
+ * ->parent ->parent
+ * | lock_list | <--------- | lock_list | ... | lock_list | <--------- | lock_list |
+ * | -> L1 | | L1 -> L2 | ... |Ln-2 -> Ln-1| | Ln-1 -> Ln|
+ *
+ * , so it's natural that we start from @leaf and print every ->class and
+ * ->trace until we reach the @root.
*/
static void __used
print_shortest_lock_dependencies(struct lock_list *leaf,
@@ -2332,6 +2383,61 @@ print_shortest_lock_dependencies(struct lock_list *leaf,
} while (entry && (depth >= 0));
}
+/*
+ * printk the shortest lock dependencies from @leaf to @root.
+ *
+ * We have a lock dependency path (from a backwards search) as follow:
+ *
+ * @leaf @root
+ * | |
+ * V V
+ * ->parent ->parent
+ * | lock_list | ---------> | lock_list | ... | lock_list | ---------> | lock_list |
+ * | L2 <- L1 | | L3 <- L2 | ... | Ln <- Ln-1 | | <- Ln |
+ *
+ * , so when we iterate from @leaf to @root, we actually print the lock
+ * dependency path L1 -> L2 -> .. -> Ln in the non-reverse order.
+ *
+ * Another thing to notice here is that ->class of L2 <- L1 is L1, while the
+ * ->trace of L2 <- L1 is the call trace of L2, in fact we don't have the call
+ * trace of L1 in the dependency path, which is alright, because most of the
+ * time we can figure out where L1 is held from the call trace of L2.
+ */
+static void __used
+print_shortest_lock_dependencies_backwards(struct lock_list *leaf,
+ struct lock_list *root)
+{
+ struct lock_list *entry = leaf;
+ const struct lock_trace *trace = NULL;
+ int depth;
+
+ /*compute depth from generated tree by BFS*/
+ depth = get_lock_depth(leaf);
+
+ do {
+ print_lock_class_header(entry->class, depth);
+ if (trace) {
+ printk("%*s ... acquired at:\n", depth, "");
+ print_lock_trace(trace, 2);
+ printk("\n");
+ }
+
+ /*
+ * Record the pointer to the trace for the next lock_list
+ * entry, see the comments for the function.
+ */
+ trace = entry->trace;
+
+ if (depth == 0 && (entry != root)) {
+ printk("lockdep:%s bad path found in chain graph\n", __func__);
+ break;
+ }
+
+ entry = get_lock_parent(entry);
+ depth--;
+ } while (entry && (depth >= 0));
+}
+
static void
print_irq_lock_scenario(struct lock_list *safe_entry,
struct lock_list *unsafe_entry,
@@ -2446,10 +2552,7 @@ print_bad_irq_dependency(struct task_struct *curr,
lockdep_print_held_locks(curr);
pr_warn("\nthe dependencies between %s-irq-safe lock and the holding lock:\n", irqclass);
- prev_root->trace = save_trace();
- if (!prev_root->trace)
- return;
- print_shortest_lock_dependencies(backwards_entry, prev_root);
+ print_shortest_lock_dependencies_backwards(backwards_entry, prev_root);
pr_warn("\nthe dependencies between the lock to be acquired");
pr_warn(" and %s-irq-unsafe lock:\n", irqclass);
@@ -2667,8 +2770,18 @@ static int check_irq_usage(struct task_struct *curr, struct held_lock *prev,
* Step 3: we found a bad match! Now retrieve a lock from the backward
* list whose usage mask matches the exclusive usage mask from the
* lock found on the forward list.
+ *
+ * Note, we should only keep the LOCKF_ENABLED_IRQ_ALL bits, considering
+ * the follow case:
+ *
+ * When trying to add A -> B to the graph, we find that there is a
+ * hardirq-safe L, that L -> ... -> A, and another hardirq-unsafe M,
+ * that B -> ... -> M. However M is **softirq-safe**, if we use exact
+ * invert bits of M's usage_mask, we will find another lock N that is
+ * **softirq-unsafe** and N -> ... -> A, however N -> .. -> M will not
+ * cause a inversion deadlock.
*/
- backward_mask = original_mask(target_entry1->class->usage_mask);
+ backward_mask = original_mask(target_entry1->class->usage_mask & LOCKF_ENABLED_IRQ_ALL);
ret = find_usage_backwards(&this, backward_mask, &target_entry);
if (bfs_error(ret)) {
@@ -2718,7 +2831,7 @@ static inline bool usage_skip(struct lock_list *entry, void *mask)
* <target> or not. If it can, <src> -> <target> dependency is already
* in the graph.
*
- * Return BFS_RMATCH if it does, or BFS_RMATCH if it does not, return BFS_E* if
+ * Return BFS_RMATCH if it does, or BFS_RNOMATCH if it does not, return BFS_E* if
* any error appears in the bfs search.
*/
static noinline enum bfs_result
@@ -4577,7 +4690,7 @@ static int check_wait_context(struct task_struct *curr, struct held_lock *next)
u8 curr_inner;
int depth;
- if (!curr->lockdep_depth || !next_inner || next->trylock)
+ if (!next_inner || next->trylock)
return 0;
if (!next_outer)